Test Details

Geometry

Mathe

Jan 20, 8:00 PM

60 minutes

Jan 20, 9:00 PM

15.0 marks

MCQ

10 questions

shimbhoo nishad

Class Details

Mathe

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Question Text

Question 1 :
In the given figure, ∆ABC ~ ∆QPR. Then ∠R is <img style='object-fit:contain' src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ef19e5a1766ce1c2c83a5c7"/>

Question 2 :
In the given figure, AB is a diameter of the circle. If AC = BC, then ∠CAB is equal to <img style='object-fit:contain' src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ef19e6a6150ce6eb5a146ea"/>

Question 3 :
In the given figure, if ∠DAB = 60° and ∠ABD = 50° then ∠ACB is equal to <img style='object-fit:contain' src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ef19e6b819305523f232922"/>

Question 4 :
If in two triangles ABC and PQR, {tex}\frac { AB }{ QR } =\frac { BC }{ PR } =\frac { CA }{ PQ } {/tex} then

Question 5 :
If in triangles ABC and DEF,{tex}\frac { AB }{ DE } =\frac { BC }{ FD } {/tex} , then they will be similar when

Question 6 :
From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is

Question 7 :
If ∆ABC ~ ∆PQR, BC = 8 cm and QR = 6 cm, then the ratio of the areas of ∆ABC and ∆PQR is

Question 8 :
In the given figure, PA and PB are tangents to a circle with centre O. If &ang;APB = 50°, then &ang;OAB is equal to  <img style='object-fit:contain' class="uploaded-image" src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ff2dee54e882678264ecf43" />

Question 9 :
In the given figure, PQ and PR are tangents from P to a circle with centre O. If ∠POR = 55°, then ∠QPR is <img style='object-fit:contain' src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ef19e716150ce6eb5a146f9"/>

Question 10 :
In the given figure, if sides PQ, QR, RS and SP of a quadrilateral PQRS touch a circle at points A, B, C and D respectively, then PD + BQ is equal to <img style='object-fit:contain' src="https://storage.googleapis.com/teachmint/question_assets/ICSE%20-%20Class%2010%20/5ef19e7c6150ce6eb5a1470c"/>

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