Question 1 :
The point which lies in the perpendicular bisector of the line segment joining the points A (-2, -5) and B (2,5) is
Question 2 :
Find the co-ordinates of the mid point of a point that divides AB in the ratio 3 : 2.
Question 4 :
The coordinates of the midpointof a line segment joining$P ( 5,7 )$ and Q $( - 3,3 )$ are
Question 5 :
$M(2, 6)$ is the midpoint of $\overline {AB}$. If $A$ has coordinates $(10, 12)$, the coordinates of $B$ are
Question 6 :
The points $A$ $(x_1, y_1), B (x_2, y_2)$ and $C (x_3, y_3)$ are the vertices of $\Delta $ ABC.<br/>The median $AD$ meets $BC$ at $D$.<br/>Find the coordinates of points Q and R on medians BE and CF, respectively such that $BQ : QE = 2 : 1$ and $CR : RF = 2 : 1$.<br/>
Question 7 :
The coordinates of the point which divides the line segment joining the points $(-7, 4)$ and $(-6, -5)$ internally in the ratio $7 : 2$ is:
Question 8 :
The mid-point of line segment joining thepoints (3, 0) and (-1, 4) is :
Question 9 :
Select the correct option.<br>The value of $p$, for which the points $A(3,1) , B (5, p)$ and $C (7, -5)$ are collinear, is
Question 10 :
The ratio by which the line $2x + 5y - 7 = 0$ divides the straight line joining the points $(-4, 7) $ and $(6, -5)$ is
Question 11 :
The point P divides the line segment joining the points $\displaystyle A\left ( 2,1 \right )$ and $\displaystyle B\left ( 5,-8\right )$ such that $ \frac{AP}{AB}=\frac{1}{3}$ If P lies on the line $\displaystyle 2x+y+k=0$<br/>then the value of k is-
Question 12 :
Find the ratio in which the line segment joining the points $(3,5)$ and $(-4,2)$ is divided by y-axis.<br/>
Question 13 :
The line segment joining the points $(3, -4)$ and $(1, 2) $ is trisected at the points P and Q. If the and co-ordinates of P and Q are $(p, -2)$ and $(\frac{5}{3}, q)$ respectively, find the value of p and q.
Question 14 :
$A(5,1)$, $B(1,5)$ and $C(-3, -1)$ are the vertices of $\Delta ABC$. The length of its median AD is:
Question 15 :
Let $A(-6,-5)$ and $B(-6,4)$ be two points such that a point $P$ on the line $AB$ satisfies $AP=\cfrac{2}{9}AB$. Find the point $P$.
