Question 1 :
Find the area of an equilateral triangle with side P cm.<br>Find the area of a triangle whose base is 12cm and height is $5\sqrt 2 cm.$
Question 2 :
Consider a rectangle of length $4$ cm and breadth $3$ cm. Find the area of given rectangle with suitable units.
Question 3 :
Let there be a rectangle of area $24\ cm^{2}$. Then find the total number of square grids made in this rectangle.(Each square grid measures $1\ cm^{2}$)
Question 4 :
The side of a square is $10 cm$. How many times will the new perimeter become if the side of the square is doubled?
Question 5 :
Form a rectangle with $8$ square grids where each square grid measure $1\ cm^{2}$. Find the total area of the rectangle.
Question 7 :
Consider a rectangle of perimeter $24\ cm$ with sides $a$ and $b$. Then the total number of square grids formed in that rectangle is given by
Question 8 :
The area of a rectangle of length (x + 2) units and breadth (x -8) units is
Question 9 :
A closed box made of steel of uniform thickness has length breadth and height 12 dm, 10 sm and 8 dm respectively If the thickness of the steel sheet is 1 dm then the inner surface area is
Question 10 :
Take a circle with radius $5$ m, then determine the area of given circle with suitable units.
Question 11 :
State whether the statement is true or false.$ \displaystyle \frac{4}{-9}   $ and $ \displaystyle \frac{-16}{36}   $ represent the same rational number?
Question 13 :
If a cellphone costs Rs.$999$. What is the cost of $12$ such cellphones?
Question 16 :
How many rational numbers exist between any two distinct rational numbers?
Question 17 :
On a scale of map $1.5 \,cm$ represents $24\, km$. If the distance between two points on the map is $76.5\, cm$, then the actual distance between these points is.
Question 18 :
Solve it <br/>$\dfrac {\left( {{{\left( {245 + 232} \right)}^2} - {{\left( {245 - 232} \right)}^2}} \right)}{\left( {245 + 232} \right)}$
Question 20 :
$\displaystyle 40- \frac { 1 }{ 2 }\times ........ = 1$
Question 23 :
$\frac {171\tfrac {3}{4}\times 171\tfrac {3}{4}-91\tfrac {3}{4}\times 91\tfrac {3}{4}}{171\tfrac {3}{4}+91\tfrac {3}{4}}$ is equal to
Question 26 :
The value of $0.\bar { 1 } +0.0\bar { 1 } +0.00\bar { 1 } $ is equal to