Page 1 :
Force:, , 7. When a force acts on body, the body goes in linear motion., A. Stationary rigid body., , B. Stationary flexible body., , C, The pivoted rigid body., , D. None of the Above., , Ans: A., , 2. When a force acts on body, the body goes in rotationalmotion., A. A rigid body pivoted at a point., , B. Stationary flexible body., , C. The pivoted rigid body., , D. None of the Above., , Ans: A., , 3. S|. Unit of moment of force is,, A. newton meter., , B.Nm., , C. Dyne cm., , d. Kgf m., , Ans: A., , 4, The rotation is always produce by a, A. Applied force., , B. Pair of forces., , C. Pull and push., , D. All of the above., , And: B., , 5. A book kept on a table is an example of,, A. Dynamic equilibrium., , B. Static equilibrium., , C. Both., , D. None., , Ans: B., , 6. A body is said to be in equilibrium when,, A: It does not move., B. It has equal forces on both the sides., C. When the algebraic sum of moment of all forces acting on the body is zero., z ae body is balanced in all sides., ns: C., , 7. A body is pivoted and a force of 20 N is applied at a distance of 60 cm from the pivot. The, moment of the force is,, , A.12.N, , B. 1200 N.m, , C.12Nm., , D. 1200 N cm., , Ans: B.

Page 2 :
8. Calculate the moment of force F1 at O, , F,=3N, F,=5N Fig. 1.28, , A.10 N m clockwise., , B, 10 N m anticlockwise., , C. 12 N m clockwise., , D. 12 N m anticlockwise., , Ans: B., , 9. Two forces each of magnitude 10N act vertically upwards and downwards respectively at, the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as, shown. Determine the magnitude of resultant moment of forces about the pivot 0, , 10N, , , , 10N, , A. 40 N m anticlockwise., B. 40 Nm (clockwise)., C.0., , D. 80 N m Anticlockwise, Ans: B, , 10. The factor on which the position of centre of gravity of a body depend,, A. Its shape i.e. on the distribution of mass., , B. It does not depend upon shape but only on size., , 5 — on the earth., , Ans: A., 11. When a boy weighing 20 kgf sits at one end of a 4m long see-saw, it gets depressed at, , its end. He can be brought to the horizontal position by a man weighing 40 kgf by applying, the force at

Page 3 :
ra2owPr, HA FMP, @3933, , Ns:, , 12. The center of gravity of a circular ring is, A. On the ring., , B. At half the distance from the center., , C, At the center of the ring., , D. None of the above., , Ans: C., , 13. The centre of gravity of a hollow cone of height h is at distance x from its vertex where, the value of x is:, , (a) h/3, (b) h/4, (c) 2h/3, (a) 3h/4, Ans: C., , 14. The centripetal force is defined as the, , A. Force acting on a body moving in a circular path, in a direction towards the centre of, circular path., , B. The force acting on a body moving in a circular path, in a direction away from the centre, of circular path., , C. The force acting on a body moving in a circular path, tangent to the circle., , D. None., , Ans: A., , 15. This force is fictitious force., A. Moment of force., , B. Centrifugal force., , C. Centripetal force., , D. Electrostatic force., , Ans: B., , 16. Which of the following quantity remains constant in uniform circular motion:, (a) Velocity, , (b) Speed, , (c) Acceleration, , (d) Both velocity and speed Solutions:, , Ans: D., , 17. The moment of force is a, A. Scalar quantity., , B. Vectar Quantity., , C. Non measurable quantity., D. None., , Ans: B., , 20. One of the factors affecting the turning effect of a force., A; The magnitude of the energy applied.

Page 4 :
B. The magnitude of the force applied., , C, The magnitude of the gravity working., D. The friction between the moving parts., Ans: D., , 21., , , , The disc will rotate in, , A. Circular direction., , B. In the direction of the applied force., C. Clockwise moment., , D. Anticlockwise moment., , Ans: D., , , , F, , 22. The moment of force about a given axis depends:, , (a) Only on the magnitude of force, , (b) Only on the perpendicular distance of force from the axis, , (c) Neither on the force nor on the perpendicular distance of force from the axis, , id) oa on the force and its perpendicular distance from the axis. Solution:, ns; D., , 23. A body is acted upon by two unequal forces in opposite directions, but not in the same, line. The effect is that:, , (a) The body will have only the rotational motion, , (b) The body will have only the translational motion, , (c) The body will have neither the rotational motion nor the translational motion, , i) a” body will have rotational as well as translational motion. Solution:, ns: D,, , 24. A nut is opened by a wrench of length 20 cm. If the least force required is 5.0N, find the, moment of force needed to turn the nut., , A: 0.5 Nm, , B.1Nm., , C.10 Ncm., , D. 100 Ncm, , Ans: B., , 25. The diagram shows a uniform bar supported at the middle point O. A weight of 40 gf is, placed at a distance 40cm to the left of the point O. How can you balance the bar with a, weight of 80 gf?, , 40 of, , 50 40 30 20 10 10 20 30 40 50 cm, , A: 40 cm from 0.

Page 5 :
B. 20 cm from 0., , C, 40 cm from 50 cm on the left side., D. At the center of gravity., , Ans: B., , = It is easier to turn the steering wheel of a large diameter than that of a small diameter, cause,, , A. To turn the steering wheel of a large diameter need less force which is at a large distance, from the centre of rim., , B. To turn the steering wheel of a large diameter need negligible force which is at a large, distance from the centre of rim., , C. To turn the steering wheel of a large diameter maximum force which is at a large, distance from the centre of rim,, , D. large wheels can turn easily., , Ans: A., , 27. A jack screw is provided with a long arm, A. Trucks need more powerful jack screw., B. Long arms can easily reach the interior of the wheel., C, A long arm of a jack screw which is used to lift a heavy load like a vehicle will help to, apply less effort which is required to rotate it to raise or lower the jack., B All e the above., ns; C., , 28.A __is always required to produce the rotation., A: Energy., , 2. Force., , C. Couple., , D. All the above., , Ans: C., , 29. is always taken to be positive., A. Clockwise moment., , B. Anticlockwise of moment., , C, Moment of force., , D. Principle of moment., , Ans: B., , 30, The center of gravity of triangular lamina lies at, A. Midpoint., , B. The midpoint of interaction of medians., , C, At 3/4» h., , D. At the 1/4h h of the median., , Ans: B., , Work, Energy, Power:, , Q1. What is the SI unit of Work?, A: Joule, , B: erg, , Cc: g-cm