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Mathematics, (www.tiwariacademy.com), (Chapter - 8) (Introduction to Trigonometry), (Class 10), Exercise 8.2, Question 1:, Evaluate the following:, (i) sin 60° cos 30° + sin 30° cos 60°, cos 45°, (ii) 2 tan? 45° + cos² 30° – sin? 60°, sin 30°+tan 45°-cosec 60°, (iii), sec 30°+cosec 30°, (iv), sec 30°+cos 60°+cot 45°, 5 cos? 60°+4 sec² 30°-tan? 45°, (v), sin? 30°+cos2 30°, Answer 1:, (i) sin 60° cos 30° + sin 30° cos 60°, Putting the value of each trigonometric ratios, we get, (9(9。自, V3, V3, 3, 1, 4, = 1, 4, 4, (ii) 2 tan? 45° + cos? 30° – sin? 60°, Putting the value of each trigonometric ratios, we get, 2, 3, 2(1)² +, = 2 +, ---= 2, 4, 4, cos 45°, (iii), sec 30°+cosec 30°, Putting the value of each trigonometric ratios, we get, 1, 1, V3, V3, V2, 2, + 2, V3, vZ(2 + 2v3), 2 + 2/3, V3, 2/2 – 2/6, 2/2 + 2V6, IWARI, 2v6 – 6v2_ -2(3v2 – V6), V3, 2/6 - 2V18, 2V2 + 2v6^ 2v2 – 2v6 (2v2) – (2V6), 8 – 24, -16, maths by Saurabh sir, 8386933755, 3/2 - V6, 8., sin 30°+tan 45°-cosec 60°, (iv), sec 30°+cos 60°+cot 45°, Putting the value of each trigonometric ratios, we get, V3 + 2/3 – 4, 2V3, 2, 5+1, 3/3 – 4, V3, 4 + V3 + 2/3, 2/3, 2, 1, 3V3 + 4, 5+1, V3, 3/3 – 4 3V3 – 4, 27 – 12/3 – 12/3 + 16, 3/3 + 4 3V3 – 4, (3v3) – 42, 43 – 24/3, 43 – 24/3, %3D, 27 – 16, 11