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E., - Br and Br has higher, CH,CH,, Some more examples are:, CH,CH,CH,, CH,CH, ., CH,CH,CH,, pune, CH;, C., CH;, H., E-3-Ethyl-2hexene, Solution., CH;, In co, Z-3-Ethyl-2-hexene, an, F, Cl, CH,-ar, configural, C., C., and, C., Br, Br, I., Z-1-Bromo-2-chloro, 2-fluoro-1-iodoethene, E-1-Bromo-2-chloro, 2-fluoro-1-iodoethene, Example 1. Assign E and Z configurations to the following compounds., CH,CH,, (ii) ' CH,, I CH3, (!), C-C, (1) \ CH,, HE, E `CH(CH,);!, (iv) \CH,, つ 0, Solution., H., HOO, In tra, C;H,, (!), C=C, 3 HG, | CHO, HOO-, Geometr, HD\ (4), C=C, Oxime, geometrica, sides of th, and anti (, C=C, 2Br, NHCH,, HOO)!, Br, 1., Solution. (i) CH,, CH, C=C, %3D, H., Out of-CH, and H,-CH,, has higher priority, out of -, priority. Groups of higher priority lie on the same side. Therefore the configuration is 2., -, Geom, (ii) CH;, CH,CH;, may be she, CH(CH;),, - CH(CH,)2 has higher priority. The groups of higher priority lie on opposite sides of, bond. Therefore the configuration is E., Following the same analogy, the students can see the configurations of compounds, (v) and (ví) are Z, E, E and E respectively.