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23. ADDITION BASE METHOD, , , , Example: 26+39 here the base 10is taken, Step-1 Subtract the units digit of second addend from base, 10. Again subtract the, difference from units place of first addend., , eg. 26 (-1) I. 10-9 =1, +39 ii. 6-1=5, 5, Step-2 Add the successor of tens place digit of second addend to first addend., 26 2+4= 6 (4 is successor of 3), +39, 65 Here is the answer, 26 + 39= 65, , 2nd case: For of triple digits addition, the base 100 is taken., , Step-1 | Subtract the numbers at tens & ones place from 100., Subtract the difference, 01 from 49, tens place & ones digit of first addend., , eg. 249 (-01) (49-01=48) [Subtract 99 from 100, answer is 1. Subtract, a from tens & ones place no. i.e. 49], , Step-2 Add the successor of hundreds place digit of second addend to hundreds, place digit of first addend., , 249 (2+2=4) [ successor of 1 is 2], , + 199, 448 Here is the answer, 249 + 199= 448