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SHREE GURU GYAN TUTORIALS, Std 12: MATHS, Date:14/02/22, Chapters:2, Total Marks:28, PAPER 1 TAXBOOK BASED MCQ, Time: 03Hour, Section A, Choose correct answer from the given options. [Each carries 1 Mark], [28], 1., tan (cot x) + cot (tan x) =, 0 < x <, (A) T - x, (В) 2х, (C) T - 2x, (D) -2x, 2., sec2 (tan-1 4) + cosec2 (cot-15) =, %3D, (A) 41, (B) 43, (C) 45, (D) 47, 3., If cotx - cotly 0 and cosx + cosly, then x + y =, %3D, 2, 1, (A), (D) 2, (B) 1, (C) 0, 3n, sin-lx + sin-ly + sin-lz, and f(1) = 2, f (p + q) f(p) f (q), V p, q e R then xf(1) + yf (2), 4., %3D, 2, x + y + z, + zf(3), + y(2), + zf(3), (A) 0, (B) 1, (C) 2, (D) 3, -1 4, If x sin(2 tan-1 2) and y = sin, tan, then, 3, 5., (A) x = 1 - y, (B) x2 = 1 - y, (C) x = 1 + y, (D) x = 4y2, (cos(cot"(sec(isin"la)), 6., cosec tan, 1, -1, (A), V3 - a?, (B) - V3 -, a?, (C) 3 - a?, (D), a?, 1, If cos(2 sin- x) = a then x = ..., 7., 9., 3, (A), 2, (B), (C), (D) 1, sin?(cosx) + cos2 ( sin V1, ...(0 < x < 1), 8., (A), 2, (B), (C) 1, (D) = 0, cor"(cos")-, cota, 9., 2, (B), 3, (A) 1, (C), (D) 5, 10., If 4 sin-lx + 3 cos-lx = 2n then x =, (A) 0, (B) 1, 1, (C), (D), If n s x < 2n then cos (cos x) =, (A) x, 11., (В) — х, (C) 2n + x, (D) 2n - x, 12., The solution set of sin-lx s cosx is, 1, (A), 1, 1, 1, (B), (C), 1,, (D), Wish You - All The Best, 1, 1/2
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13., tan-(1) + tan-(2) + tan-(3), %3D, (A) n, (B), 4, (C), (D) None of these, 14., flx), sin-lx + tan-x + secx then range of f(x) is, %3D, T 3n, T 3n, (4' 4, (A), 4' 4, (B), 4' 4, (C), (D) None of these, 15., The solution set of sin (sin5') > x - 4x is, (A) |x – 2|< 9 – 2n, (B) |x - 2|> J9 - 2n, (C) |x|< /9 - 2n, (D) |x|> 9, - 2n, 16., The number of real solutions of (x, y), where y sin(sin x) and |y| = cos x, |x| < 3n is, (A) 2, (B) 4, (C) 6, (D) 8, 1, 9n, sin, cos-, 10, -1, 9n, 17., The principle value of cos, is, 17T, 7n, (A), 20, (B), 20, (C), 10, (D) None of these, 18., The roots of the equation &r2 + 22x + 5 0 are 0 and o. then, (A) sin-le and sin-lo, both the real, (B) sec-10 and sec-lo, both the real, (C) tan-10 and tan-lo, both the real, (D) None of these, The solution set of the equation tan-x - cot'x = cos(2 - x) is .., (A) [0, 1], 19., (В) [-1, 1], (C) [1, 3], (D) None of these, 20. sin- (cos(sin-x) + cos(sin(cosx) =, %3D, (B) 2, (C), (A), 4, (D) 0, cos (2cos-lx + sin-'x), 1, where x =, 21., %3D, 2/6, (B), (A), 5, (C), (D) None of these, 1, f(x), = sin-1 V3, 1, Sxs1 then f(x) =, 22., -V1 - x2, X -, 2, 1, - sin-, 2, (B) sin-x -, (A) sin-1, (C) sin-, (D) None of these, -1, sin 4 tan, 3., 23., 12, 13, 24, 24, (A), 25, (B), 25, (C), 25, (D), 25, If sin-!x + sin-l'y% =, 2n, then cos-lx + cos-ly, 3, 24., (A), (B) 3, (C), (D) T, 25., Domain of sin-! is, (A) [0, 1], (B) (-0o, o0), (C) [0, n], (D) -1, 1], (), 26., cos cos, + sin-, 1, (A), 3, 4, (B), (C) 0, (D), 3, 27., The value of sin-!, sin, is, Wish You - All The Best, 2, RIN
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2n, (A) -3, (B), 3, (C), (D), 3, 28., sec2(tan-13) + cosec2(cor13), (A) 20, (B) 15, (C) 13, (D) 25, Wish You - All The Best, 3
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SHREE GURU GYAN TUTORIALS, Std 12: MATHS, Chapters:2, Total Marks:28, Date:14/02/22, PAPER 1 TAXBOOK BASED MCQ, Time: 03Hour, Section A, Choose correct answer from the given options. [Each carries 1 Mark], [28], 1., tan-(cot x) + cot(tan x) =, 0 < x <, (A) n - x, (B) 2x, (C) n - 2x, (D) -2.x, Ans (C) n - 2x, tan-(cot x) + cot-(tan x), - cot (cot x) +, 2, - tan (tan x), 2, %3D, and tan-le + cotle =, :), 2, > x > 0), TC, - x +, 2, %3D, = n - 2x, 2., sec2 (tan-1 4) + cosec2 (cot- 5) =, (A) 41, (B) 43, (C) 45, (D) 47, Ans (B) 43, sec? (tan-1 4) + cosec2 (cot- 5) in, Take tan- 4 = x and cot 5 = y, tan x = 4 and cot y = 5, Now sec?x = 1 + tan?x and cosec?y = 1 + cot?y, = 1 + 16, = 1 + 25, = 17, = 26, sec2(tan-1 4) + cosec2(cot 5), = sec?x + cosec2y, = 17 + 26, = 43, If cot-x - cot-ly 0 and cos-lx + cos-ly =, then x + y = .........., 2, 3., 1, (A) J2, (D) 2, (B) 1, (C) 0, Ans (D) 2, cot'r- cotly = 0 = cot'x = cotrly, %3!, = x = y, nðu cos-lx + cos-ly, 2, .. cos-lx + cosx =, (: x = y), Welcome To Future- Quantum Paper