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Subject Code - 041, , Sample Question Paper, CLASS: XII, Session: 2021-22, Mathematics (Code-041), Term - 2, Time Allowed: 2 hours, Maximum Marks: 40, General Instructions:, 1. This question paper contains three sections β A, B and C. Each part is compulsory., 2. Section - A has 6 short answer type (SA1) questions of 2 marks each., 3. Section β B has 4 short answer type (SA2) questions of 3 marks each., 4. Section - C has 4 long answer type questions (LA) of 4 marks each., 5. There is an internal choice in some of the questions., 6. Q14 is a case-based problem having 2 sub parts of 2 marks each., , SECTION β A, 1., , 2, , ππππ₯, , Find β« (1+ππππ₯)2 ππ₯, OR, π ππ2π₯, , Find β« β9βπππ 4 ππ₯, π₯, , 2., , Write the sum of the order and the degree of the following differential, equation:, π, , 2, , ππ¦, , ( )=5, ππ₯ ππ₯, 3., , If πΜ and πΜ are unit vectors, then prove that, π, |πΜ + πΜ| = 2πππ , where π is the angle between them., , 2, , Find the direction cosines of the following line:, 3 β π₯ 2π¦ β 1 π§, =, =, β1, 2, 4, A bag contains 1 red and 3 white balls. Find the probability distribution of, the number of red balls if 2 balls are drawn at random from the bag one-byone without replacement., Two cards are drawn at random from a pack of 52 cards one-by-one without, replacement. What is the probability of getting first card red and second, card Jack?, , 2, , 2, , 4., 5., , 6., , 2, , 2, , SECTION β B, π₯+1, , 7., , Find: β« (π₯ 2+1)π₯ ππ₯, , 3, , 8., , Find the general solution of the following differential equation:, ππ¦, π¦, π₯, = π¦ β π₯π ππ( ), ππ₯, π₯, OR, Find the particular solution of the following differential equation, given that, π, y = 0 when x = 4 :, ππ¦, 2, + π¦πππ‘π₯ =, ππ₯, 1 + π πππ₯, βββ πβ. πββ = πβ. πβ, πβ Γ πββ = πβ Γ πβ, then show that πββ = πβ., If πβ β 0,, , 3, , 9., , 3
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10., , Find the shortest distance between the following lines:, πβ = (πΜ + πΜ β πΜ) + π (2πΜ + πΜ + πΜ ), πβ = (πΜ + πΜ + 2πΜ) + π‘(4πΜ + 2πΜ + 2πΜ), OR, Find the vector and the cartesian equations of the plane containing the point, πΜ + 2πΜ β πΜ and parallel to the lines πβ = (πΜ + 2πΜ + 2πΜ) + π (2πΜ β 3πΜ + 2πΜ) = 0, and πβ = (3πΜ + πΜ β 2πΜ) + π‘(πΜ β 3πΜ + πΜ) = 0, , 3, , SECTION β C, 2, β«β1|π₯ 3, , 11., , Evaluate:, , 12., , Using integration, find the area of the region in the first quadrant enclosed, by the line x + y = 2, the parabola y 2 = x and the x-axis., OR, Using integration, find the area of the region, {(π₯, π¦): 0 β€ π¦ β€ β3π₯, π₯ 2 + π¦ 2 β€ 4}, , 4, , 13., , Find the foot of the perpendicular from the point (1, 2, 0) upon the plane, x β 3y + 2z = 9. Hence, find the distance of the point (1, 2, 0) from the given, plane., , 4, , 2, , β 3π₯ + 2π₯|ππ₯, , 4, , CASE-BASED/DATA-BASED, , 14., , Fig 3, An insurance company believes that people can be divided into two classes: those who, are accident prone and those who are not. The companyβs statistics show that an, accident-prone person will have an accident at sometime within a fixed one-year period, with probability 0.6, whereas this probability is 0.2 for a person who is not accident, prone. The company knows that 20 percent of the population is accident prone., Based on the given information, answer the following questions., (i)what is the probability that a new policyholder will have an accident, within a year of purchasing a policy?, (ii) Suppose that a new policyholder has an accident within a year of, purchasing a policy. What is the probability that he or she is accident prone?, ---------------------------, , 2, 2