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padding ©, , therefor, observer, , opposite, , , , Questic, 126 km, retarda, the car, Solutic, 40, t(S) : packward, therefore he, 5 fo ard and 3 ster Final, As drunkard eee Bean a packware 322m eee, eps=, an es From, or, , moves 5 m forward ¢ :, , -. Distance travelled in 8sin as, 16 steps, , aX Be 6m, , Distance travelled in 16 s me Wepse, Distance travelled in 245? oe sa2x4=8m ? i, 15 steps taken in forward direction, , velled in 32 s in 32 step, s in nex, ou, 37s in 37 steps =8+ 9=13m, , Distance tra, Distance travelled in next 5, , - Total distance travelled in (32+ 5 =), 13m, , Distance of the pit from the starting poet ¥, Therefore drunkard will fall in the pit n 37S., Question 5. A jet airplane travelling at a speed of 500 km/h ejects its, products of combustion at the speed of 1500 km/h relative to the jet plane., What is the speed of the latter with respect to an observer on the ground?, Solution Let jet airplane be moving upwards right (+ve direction) with, velocity v; and ejected gases be moving downwards (—ve direction) with, velocity v, while observer be at rest on the ground i.e., v, =0 ee, V, =-1500 km/h, Rel oe, elative velocity of i, y of plane with respect to the observer, i~ Yo = 500-0 =500 km/h, Relative velocity of vl), TO :, Y Of products of combustion with res, , VG ~Vi=— 1500 km/h (given), SV, and i, g and velocity of y j Ate in opposite directions), , or, , Vv, pect to the jet plane