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my, 00, 4., 2022.03.19 12:44, KITY, Solution:, 63 = [sth observation+(5+1)th observation]/2, Mean=Average = Sum of all the observations/Total number of, 63 = [5th observation+6th observation]/2, observations, 63 (x+X+2)/2, %3D, (41+39+48+52+46+62+54+40+96+52+98+40+42+52+60)/15, 63 = (2x+2)/2, = 822/15, エ-g9 = X, X = 62, = 54.8, 4. Find the mode of 14, 25, 14, 28, 18, 17, 18, 14, 23, 22,, Median,, 14, 18., To find the median, we first arrange the data in ascending, Solution:, order., Mode,, 39,40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98, To find the mode, we first arrange the given data in ascending, Here,, order., Number of observations (n) = 15, 14,14,14,14,17,18,18 ,18,22,23,25,28, %3D, Since the number of observations are odd, the median can be, Here,, calculated as:, We find that 14 occurs most frequently (4 times), Median =, [(n+1)/2]th observation, . Mode = 14, = [(15+1)/27th observation, %3D, 5. Find the mean salary of 60 workers of a factory from the, = (16/2)th observation, following table:, = gth observation, Solution:, = 52, Number of workers (f), Mode,, 0008, 9エ, To find the mode, we first arrange the data in ascending order., 4000, 12, 0008, 39,40, 40, 41, 42, 46, 48, 52, 52, 52, 54, 60, 62, 96, 98, Here,, 000O0S, 00OS, We find that 52 occurs most frequently (3 times), 0008, O009, 8., . Mode = 52, 3. The following observations have been arranged in ascending, 00OL, order. If the median of the data is 63, find the value of x., 32000, 0008, 29, 32, 48, 50, x, X+2, 72, 78, 84, 95, 27000, O00b, 3., Solution:, O000T, Number of observations (n) = 10, 10000, Given that Median = 63, Efx; = 305000, Total, %3D, Since the number of observations are even, the median can be, cculated as:, the mean salary is a5083.33