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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Speed Time & Distance Questions With Solution, , 1. Hemant covers a certain distance with his own speed , but when he reduces his speed by 10 km/hr, his time duration for the journey increases by 40 hrs, while if he increases his speed by 5km/hr from, his original speed he takes 10hrs less than the original time taken . Find the distance covered by him., A) 1200km, B) 1500km, C) 1350km, D) 1400km, E) None, , View Answer, Option B, Solution:, Let distance be x km and speed be y km/hr, x/(y-10)-x/y=40==> x=4y(y-10) ——(1), x/y-x/(y+5)=10==>x=2y(y+5) ——-(2), Equate 1 and 2, 4y(y-10)=2y(y+5), 2y-20=y+5==>y=25km/hr, Then x=2*25(25+5)=50*30=1500km, , 2., A train met with an accident 60km away from station A. It completed the remaining journey at, 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km, further, it would have been only 1hr late. what was the original speed of the train?, A) 50km/hr, B) 45km/hr, C) 60km/hr, D) 55km/hr, E) None, , View Answer, Option C, Solution:, Let the original speed be 6x., Travelling 60km at 5/6th of original speed cost 12 mins etc., 60/5x = 60/6x +12/60, ==>x=10, Original speed 6x=60km/hr., , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 3., Two man start together to walk a certain distance, one at 4 km/hr and another at 5 km/hr. The, former arrives half an hour before the latter. Find the distance., A) 10km, B) 15km, C) 20km, D) 8km, E) None, , View Answer, Option A, Solution:, If the distance be x km, then, x/4-x/5=1/2, (5x-4x)/20=1/2, x/20=1/2==>x=10km, , 4., In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for, the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the, flight is:, A) 2hrs, B) 1hr 30min, C) 2hrs 15min, D) 1hr, E) None, , View Answer, Option D, Solution:, Let the duration of the flight be x hrs., Then, 600/x-600/(x+1/2)=200, 600/x-1200/2x+1=200, X(2x+1)=3, 2x +x-3=0, X=1hr., 2, , 5., Two racers start running towards each other, one from A to B and another from B to A. They, cross each other after one hour and the first racer reaches B, 5/6 hour before the second racer reaches, A. If the distance between A and B is 50 km. what is the speed of the slower racer?, A) 15km/hr, B) 20km/hr, C) 25km/hr, Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , D) 30km/hr, E) None, , View Answer, Option B, Solution:, Let second racer takes x hr with speed s2, First racer takes x-5/6 hr with speed s1, Total distance = 50km, S1 = 50/(x-(5/6)), S2= 50/x, As they cross each other in 1hr…, Total speed = s1 + s2, Now, T = D / S, 50/(s1+s2) = 1, x = 5/2, 1/3, Put x= 5/2 in s2 –> 20km/hr, 6., P and Q run at the speed 40m/s and 20m/s resp on the circular track of 800m, as its, circumference , when would the P and Q meet for the first time at the starting point if they start, simultaneously from the same point., A) 40sec, B) 50sec, C) 55sec, D) 60sec, E) None, , View Answer, Option A, Solution:, Time taken by P to complete one round, 800/40=20, Time taken by Q to complete one round, 800/20=40, LCM of 20 40=40, Every 40sec they would be together at the starting point., , 7., The speeds of Ram and Raj are 30 km/h and 40 km/h. Initially Raj is at a place L and Ram is at, a place M. The distance between L and M is 650 km. Ram started his journey 3 hours earlier than Raj, to meet each other. If they meet each other at a place P somewhere between L and M, then the distance, between P and M is?, A) 225km, B) 300km, C) 250km, D) 330km, E) None, Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , View Answer, Option D, Solution:, If the 1st 3hr Ram covers 90km, So the rest 650-90=560km, Now they both travel together towards each other, So, the time is 560/70=8hr, Then ram travel total 3+8=11hrs, Thus the distance travelled by Ram 11*30=330km, , 8., The ratio between the speed of a car and a bike is 16 : 15 respectively. Also, a bus covered a, distance of 480 km in 8 hrs. The speed of the bus is three-fourth the speed of the car. How much, distance will the bike cover in 6 h?, A) 320km, B) 360km, C) 450km, D) 435km, E) None, , View Answer, Option C, Solution:, Speed of bus = 480/8 = 60km/ h, Speed of car = (60*4)/3=80 km / h, Speed of car : Speed of bike = 16 : 15, Speed of bike =80/16 * 15 = 75 km/ h, Distance covered by bike in 6 hr = 75 × 6 = 450 km, 9., How many seconds will a train 50 m in length, travelling at the rate of 42 km an hour, rate to, pass another train 80 m long, proceeding in the same direction at the rate of 30 km an hour?, A) 45sec, B) 39sec, C) 50sec, D) 55sec, E) None, , View Answer, Option B, Solution:, Relative speed =42-30=12km/hr, Time= (50+80)*18/12*5, =130*18/12*5==>13*3, =39sec., , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 10., A man rides his bike 20 km at an average speed of 8 km/hr and again travels 45 km at an, average speed of 10 km/hr. What is his average speed for the ride approximately?, A) 10.8km/hr, B) 8.5km/hr, C) 9.3km/hr, D) 10.2km/hr, E) None, , View Answer, Option C, Solution:, Average speed=total distance/total time, Total time=20/8 + 45/10, Avg speed=(20+45)/(20/8 + 45/10), = 65/((200+360)/80), =65*80/560 = 65/7, =9.3km/hr, , 1. Two buses start at same time from Chennai and Bangalore, which are 250km apart. If the two buses, travel towards each other, they meet after 1hr and if they travel in same direction they meet after, 5hrs. What is the speed of the bus starts from Chennai if it is know that the one which started from, Chennai has more speed than the other one?, A) 150km/hr, B) 100km/hr, C) 45km/hr, D) 80km/hr, E) 120km/hr, , View Answer, Option A, Solution:, S=D/T, Here we have two speeds. We get 2 equations as., 250/1hr = C+B—-1 (Travelling in opposite direction, speed must be added ie C+B), 250/5hr = C-B—-2 (Travelling in same direction, speed to be subtracted. ie C-B), solving 2 eqn C=150km/hr., 2., Car A leaves the city at 5pmm and is driven at a speed of 30km/hr. 3hrs later another car B, leaves the city in the same direction as car A. In how much time will car B be 12kms ahead of car A if, the speed of car B is 50km/hr?, A) 5hrs, B) 4.2hrs, C) 8hrs, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , D) 5.1hrs, E) 12hrs, , View Answer, Option D, Solution:, Car A travels 3hrs. 3*30=90km, Difference between speeds 50-30=20km/hr, Distance ahead 12km . 90+12=102km, T=D/S ===>102/20=5.1hrs., 3., Two train starts at the same time from Delhi and Agra and proceed towards each other at the, rate of 40km/hr and 37 1/2km/hr. When they meet it is found that one train has traveled 200km more, than the other train. What is the distance between Delhi and Agra?, A) 6200km, B) 5000km, C) 4200km, D) 4800km, E) 6000km, , View Answer, Option A, Solution:, Speed ratio 40:37 1/2==>40: 75/2==>80:75 ie 16:15, ratio diff betwwen speed is 1[16-15], 1 ===> 200 (more distance), [16+15]31 ===>?, 31*200=6200km., 4., If a car runs at 45km/hr, it reaches its destination late by 10 min but if runs at 60km/hr it is late, by 4min. What is the correct time for the journey?, A) 24min, B) 14min, C) 32min, D) 20min, E) 46min, , View Answer, Option B, Solution:, Distance = diff in time *(S1*S2)/S1-S2, D=[10-4]/60hr * (45*60)/[60-45] = 6/60 * 45*60/15 ==>18km, time T=D/S(take any one of the speed) 18/45 =2/5hrs = 2/5*60=24min, then correct time is 24-10=14mins., , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 5., A bike rider starts at 40km/hr and he increases his speed in every 1 hour by 2km/hr. Then the, maximum distance covered by him in 24 hrs is:, A) 682km, B) 540km, C) 620km, D) 612km, E) 500km, , View Answer, Option D, Solution:, Speed of the rider: 40km/hr, He increases his speed in every 1 hr by 2km/hr., Distance covered by every 1 hr will be 40,42,44….upto 12terms. i.e. (for 24hrs), Sum of 1st n terms=n/2 ( (2a+(n-1)d), 12/2 * (2*40+11*2)==>12/2 * (80+22)==>612km, 6., Two friends Ram and Ravi are travelling from point A to B, which are 600km apart. Travelling, at a certain speed Ram takes 1hr more than Ravi to reach point B. If Ram doubles his speed he will, take 1hr 30mins less than ravi to reach point B. At what speed was Ram driving from point A to B?, A) 150km/hr, B) 120km/hr, C) 80km/hr, D) 45km/hr, E) 92km/hr, , View Answer, Option B, Solution:, T = D/S. Let x be the speed, 600/x = T+1 , 600/2x = T – 3/2, Equate T, (600-x)/x = (600+3x)/2x, 1200-12x = 600+3x ==>x=120km., 7., A man takes 4hrs 30min in walking to a certain place and riding back. He would have gained, 2hrs by riding both ways. The time he would take to walk both ways, is:, A) 5hrs10min, B) 4hrs30min, C) 7hrs, D) 5hrs40min, E) 4hrs, , View Answer, Option C, Solution:, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , W+R = 4hrs 30min ie 9/2hrs, R+R=2hrs==>R=1hr, then 2W=9/2-1=7/2 , W=7/2*2=7hrs, 8., Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph, post. If the length of each train be 300 metres, in what time will they cross each other travelling in, opposite direction?, A) 25 sec, B) 18 sec, C) 14 sec, D) 12 sec, E) 20 sec, , View Answer, Option D, Solution:, Speed of the first train = [300/10] m/sec = 30 m/sec., Speed of the second train = [300/15] m/sec =20 m/sec., speed = (30 + 20) m/sec = 50m/sec., Required time = (300+300)/50secc = 12 sec., 9., The driver of a car sees a school van 60m ahead of him. After 30seconds the school van is 60m, behind. If the speed of the car is 45kmph, what is the speed of the School Van?, A) 31.8kmph, B) 20.2kmph, C) 18.6kmph, D) 26.4kmph, E) 30.6kmph, , View Answer, Option E, Solution:, Relative speed = (60+60)/30 = 4m/s = 4 * 18/5 = 14.4kmph, Speed of the school van = 45 – 14.4= 30.6kmph, 10., The distance between two cities A and B is 330km. A train starts from A at 8 AM. and travels, towards B at 60 km/hr. Another train starts from B at 9 AM. and travels towards A at 75 km/hr. At, what time do they meet?, A) 10 AM., B) 10 : 20 AM., C) 11 : 45 AM., D) 11 : 15 AM., E) 11 AM, , View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option E, Solution:, Distance travelled by first train in one hour, = 60 x 1 = 60 km, Therefore, distance between two train at 9 AM., = 330 – 60 = 270 km, Now, Relative speed of two trains = 60 + 75 = 135 km/hr, Time of meeting of two trains =270/135=2 hrs., Therefore, both the trains will meet at 9 + 2 = 11 AM., , 1. A man in a train he can count 31 telephone posts in one minute. If they are known to be 45 m apart., Find the speed of the train., A) 90 km/hr, B) 70 km/hr, C) 100 km/hr, D) 81 km/hr, E) 95 km/hr, View Answer, Option D, Solution:, speed of the train = 30*45 = (1350 *60)/1000 = 81 km/hr, 2., If a man walks from his house to office at 6 km/hr , he is late by half an hour. However, if he, walks at 8 km/hr , he is late by 10 minutes only. What is the distance of his office from his house., A) 8 km, B) 12 km, C) 14 km, D) 18 km, E) 10 km, View Answer, Option A, Solution:, (x/6)- (x/8) = (30-10)/60, => x = 8 km, 3., A candle of 8 cm long burns at the rate of 7 cm in 7 hour and another candle of 10cm long, burns at the rate of 6 cm in 3 hour. What is the time required by each candle to remain of equal lengths, after burning for some hours, when they start to burn simultaneously with uniform rate of burning?, A) 5 cm, B) 3 cm, C) 1 cm, D) 2 cm, E) 4 cm, View Answer, Option D, Solution:, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , (8 – x)=(10 – 2x), => x = 2 cm, 4., Two trains, 190 m and 170 m long are going in the same direction. The faster train takes one, minute to pass the other completely. If they are moving in opposite directions, they pass each other, completely in 3 seconds. Find the speed of each train., A) 55 m/sec. and 42 m/sec., B) 63 m/sec. and 57 m/sec., C) 60 m/sec. and 55 m/sec., D) 42 m/sec. and 40 m/sec., E) 44 m/sec. and 40 m/sec., View Answer, Option B, Solution:, let the speed of the faster train be x and the speed of the slower train be y . Then, When they move in, the same direction , the relative speed = (x – y), Total distance = 190 + 170 = 360 m, Now, dist. = speed * time = 360 = (x-y)*60, => (x – y) = 6———-(1), When the trains move in opposite direction = (x+y), 360= (x + y)*3, => 120 =(x + y) ———–(2), On solving (1) and (2), we get, x = 63 m/sec. and y = 57 m/sec., 5., A motorcyclist covered (2/3)rd of a total journey at his usual speed. He covered the remaining, distance at (3/4)th of his usual speed. As a result, he arrived 30 minutes later than the time he would, have taken at usual speed. If the total journey was 180 km. What was his usual speed?, A) 30 km/hr., B) 20km/hr., C) 50 km/hr., D) 40 km/hr., E) 60 km/hr., View Answer, Option D, Solution:, Let the usual speed be x km/hr., (1/3)rd of the journey = 180/3 = 60km, Therefore, 60 / (3x/4) – 60/x = (1/2), => x = 40 km/hr., 6., A boat running at the speed of 30 km/hr downstream covers a distance of 5 km in 10 minutes ., The same boat while running upstream at the same speed covers the same distance in 12 minutes ., What is the speed of the current?, A) 2.5 km/hr, B) 4 km/hr, C) 3.2 km/hr, D) 1.5 km/hr, E) 2.5 km/hr, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , View Answer, Option A, Solution:, x + y = (5 * 60)/10 = 30 ——–(1), and x – y = (5 * 60)/12 = 25 ———(2)From (1) and (2) , we get, x + y – x + y = 30 – 25 = 5, => y = 2.5 km/hr., 7., Two points P and Q are separated from a distance of 200 km. A car leaves from P to Q at the, same time another car leaves from Q to P. The two car meet at the end of 8 hours. If the car travelling, from P to Q travels 20km/hr. than the other. Find the speed of the faster car?, A) 15.25, B) 20.22, C) 22.5, D) 18.9, E) 21.5, View Answer, Option C, Solution:, Let the speed of the car be x km/hr and (x+20) km/hr., 8x + 8(x+20) = 200, x = 2.5, speed of the faster carr =22.5 km/hr., 8., A person takes 10 hours in walking to a place and riding back. He would have taken 5 hours, less by riding both ways.What would be the time he would take to walk both ways?, A) 5 hours, B) 15 hours, C) 12 hours, D) 10 hours, E) 8 hours, View Answer, Option B, Solution:, Time taken in walking one way and riding other way = 10 hours, Time taken in riding both the ways = 5 hours, Time taken in walking one way * 2 = 20 hours – 5 hours = 15 hours, 9., A man ride a bike at a speed of 6 km/hr from point X to point Y and came back from point Y, to point X at the speed of 8 km/hr. What is the ratio between the time taken by man in riding from X to, Y to point Y to X respectively?, A) 3 : 5, B) 4 : 3, C) 1 : 5, D) 2 : 3, E) 2 : 7, View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option B, Solution:, Required ratio = 8 : 6 = 4 : 3, 10., Ritesh drive a car at the speed of 60 km/hr from resort A to resort B. Returning over the same, route , he got stuck in traffic and took an hour longer, also he could drive only at the speed of 40 km/hr, . How many kilometers did he drive each way?, A) 122 km, B) 100 km, C) 120km, D) 100 km, E) 110 km, View Answer, Option C, Solution:, x /40 – x/60 = 1, => 20x /2400 = 1, => x = 120 km, , 1. The speed of a boat in still water is 8kmph and the speed of current is 5kmph . The boat starts from, point P and rows to point Q and comes back to point P. It takes 16 hours during this journey .Find, the distance between the P and Q ., A) 42km, B) 28km, C) 31km, D) 39km, E) 47km, , View Answer, Option D, Solution:, Between point P and Q = x/(8-5) + x/(8+5) = 16, => x = 39km, 2., To reach from point A to point B at 4pm , Anuja will have to travel at an average speed of, 18kmph . She will reach the point B at 3pm if she travels at an average speed of 24kmph . What will be, the average speed of Anuja to reach point B at 2pm ?, A) 55kmph, B) 36kmph, C) 45kmph, D) 30kmph, E) 28kmph, , View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option B, Solution:, From the ques. we get to know,, x/18 – x/24 = 1, => x = 72km, Time taken at 18kmph = 72/18 = 4 hours, Therefore ,, speed to cover 72km in 2 hours = 72/2 = 36 kmph, , 3., Minal and Dhiraj begin together writing out a novel containing 8190 line. Minal starts with the, first line , writing at the rate of 200lines per hour , and Dhiraj starts with the last line , then writes, 8189 line and so on , proceeding backward at the rate of 150 lines per hour. At what line will they, meet?, A) 5000, B) 4150, C) 4680, D) 5780, E) 5600, th, , View Answer, Option C, Solution:, Duration of time of their meet = 8190/(200+150) = 23.4 hr., Their line of meet = 200 * 23.4 = 4680 line, , 4., A person starts by a car from Kollam to Trivandram and at the same time another person starts, from Trivandram to Kollam by a car . After passing each other they complete their journey in 2 hours, and (1/2)hour resp. At what rate does the second person drives the car if the first car runs at a speed of, 40 kmph ?, A) 80kmph, B) 75kmph, C) 90kmph, D) 110kmph, E) 60kmph, , View Answer, Option A, Solution:, Ratio of speeds = √(1/2) : √2, => S1 : S2 = 1 : 2, If 1 === 40, then, 2 === 80, Therefore , S2 = 80 kmph, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 5., Suppose the telegraph poles on a railway track are 30 m apart , how many poles will be passed, by a train in 2 hours if the speed of the train is 90 km an hour ?, A) 7540, B) 8750, C) 6000, D) 5240, E) 6250, , View Answer, Option C, Solution:, Train travels the dist. = 90 * 2 = 180 km = 180000m, Therefore,, the no. of poles = 180000/30 = 6000 poles, , 6., The speeds of Vijaya and Keshav are 30kmph and 40kmph . Initially, Keshav is at a point A, and Vijaya is at a place B . The distance between A and B is 650 km . Vijaya started her journey 3, hours earlier than Keshav to meet each other . If they meet each other at a place C somewhere in, between A and B , then find the distance between C and B., A) 450km, B) 785km, C) 527km, D) 470km, E) 330km, , View Answer, Option E, Solution:, In the first 3 hours Vijaya covers 90km, so rest dist. = 560km, Now, Vijaya and Keshav travels together , towards each other., Time = Dist./Speed = 560/70 = 8hours, Thus ,Vijaya travels total = 3 + 8 = 11 hours, Thus , the dist. traveled by Vijaya = 11 * 30 = 330km, , 7., A small aeroplane can travel at 400kmph in still air . The wind is blowing at a constant speed, of 40kmph . The total time for a journey against the wind is 120min. What will be the time in minutes, for the return journey with the wind?, A) 98.18min., B) 220min., C) 114min., D) 80min., Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , E) 194min., , View Answer, Option A, Solution:, 400 – 40 = 360 kmph, Let distance be x km, Take time in hours, => 120/60 = x/360, => x = 720 km, Speed of aeroplane with the wind = 440 kmph, Therefore ,, Time taken by aeroplane with the wind = (720/440 ) * 60 = 98.18 min., , 8., There are 50 poles with a constant distance between each pole . A car takes 20 sec. to reach the, 10 pole . How much more time will it take to reach the last pole ?, A) 120.11 sec., B) 108.88 sec., C) 88.8 sec., D) 125.4 sec., E) 157.17 sec., th, , View Answer, Option C, Solution:, To reach the 10th pole, the car need to travel 9 poles, 9 poles 20 seconds, 1 pole (20/9) seconds, To reach the last (20th) pole, the car needs to travel 19 poles., 49 pole 49 x (20/9) seconds = 108.88 sec., Therefore,88.8 sec more time required to reach the last pole., , 9., A bike travels without stoppages at the rate of 60kmph and it travels with stoppages at the rate, of 52kmph. How many minutes does the bike stop?, A) 11 mins., B) 10 mins., C) 5 mins., D) 8 mins., E) 15 mins., , View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option D, Solution:, Due to stoppages, the bike can cover 8 km less per hour 60 -52 = 8, Time taken to cover 8 km =(8/60) x 60 = 8 minutes, , 10., A cat is 50 of its own leaps behind a rat. The cat takes 5 leaps per minute to the rat’s 4 leaps. If, the cat and the rat cover 8m and 5m per leap resp., what distance will the cat have to run before it, catches the rat?, A) 800m, B) 1100m, C) 900m, D) 600m, E) 500m, , View Answer, Option A, Solution:, Speed of cat = 40m/min., Speed of rat =20m/min., Relative speed = 40 – 20 = 20m/min., Diff. in dist. = 50 * 8 = 400m, Time in catching the rat = 400/20 = 20min., Dist. traveled in 20min. = 20 * 40 = 800m, , 1. Two trains are running with speed 40kmph and 60kmph in the same direction. A man in the slower, train passes by the faster train in 36seconds. Find the length of faster train?, A) 100mtr, B) 150mtr, C) 200mtr, D) 250mtr, E) 300mtr, View Answer, Option C, Solution:, In the same direction speed … 60 -40 =2okmph, 20* 5/18 * 36 =200mtr, 2., After travelling two hours a train met with an accident due to this it stops for an hour. After, this the train moves at 66(2/3)% speed of its original speed and reaches to destination 3hour late. If the, accident would occur at 200km ahead in the same line then the train reaches only 2.5hours late. Then, find the distance of journey and the original speed of the train?, A) 2400km,600kmph, B) 1800km,300kmph, C) 2400km,400kmph, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , D) 1800km,200kmph, E) 2000km,100kmph, View Answer, Option B, Solution:, Due to 200km it saves 5hrs., For 3hrs it has to run 200*2*3 =1200km, 66(2/3)% = 2/3, ., after………..normal, speed, 2, :, 3, time, 3, :, 2, ., 3-2 =1., 1 =2 ( train stops for 1 hr out 3hrs. so 3-1 =2), 2 =4, 1200/4 = 300kmph, so 2hr*300 = 600km, Now total distance = 1200 +600 = 1800km, 3., A man travels a distance in three equal parts. He covers first part at 20kmph,second part at, 40kmph and third part at 120kmph. Find the distance if he covers total distance in 20hrs., A) 1400km, B) 1200km, C) 1440km, D) 1600km, E) 1500km, View Answer, Option C, Solution:, Distance = average speed * time, Average speed will be….72kmph, 72*20 =1440km, 4., A person who can walk down a hill at the rate of 6kmph and climb up the hill at rate of 4kmph., He ascends and comes down to his starting point in 5hrs. how far did he ascends ?, A) 12km, B) 14km, C) 20km, D) 24km, E) 16km, View Answer, Option A, Solution:, First find average speed = 2*6*4/(6+4), Time = 5hrs, distance = 48/10 * 5 =24, one side distance = 24/2 =12km, 5., A student walks from his house at a speed of 2(1/2)km per hour and reaches his school, 6minutes late. The next day he increases his speed by 1kmph and reaches 6minutes before school time., , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 8., A man covers a distance in downstream at 18kmph. If the speed of stream is 2kmph then find, his speed in upstream?, A) 12kmph, B) 14kmph, C) 16kmph, D) 18kmph, E) 20kmph, View Answer, Option B, Solution:, ., 18 – 2 – 2= 14kmph, 9., The distance between a thief and apolicemen is 300m. the speed of thief is 12m/s and the speed, of police is 15m/s. find the distance covered by police to catch the thief?, A) 1000m, B) 1200m, C) 1500m, D) 2000m, E) 1300m, View Answer, Option C, Solution:, ., 300/(15-12) =100sec, 15*100 = 1500m, 10., Two trains of same length passes each other in 36sec. if the speed of trains are 40kmph and, 20kmph respectively, then find the length of train?, A) 200 m, B) 400 m, C) 600 m, D) 300 m, E) 500 m, View Answer, Option D, Solution:, 2x/(40+20) * 18/5 = 36, 2x= 600, x = 300m, , 1. A man covers a distance in 10hrs and in three equal parts. The speed is 10kmph, 20kmph and, 60kmph respectively. Find the distance?, A) 240km, B) 300km, C) 150km, D) 180km, View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option D, Solution:, Distance = speed * time, Here we need average speed. So average speed will come 18kmph, Distance = 18*10 = 180km, 2., Two persons covers same distance at 42kmph and 48kmph respectively. They find that the, slower one takes 30minutes more to cover the distance. Find the distance cover by them?, A) 150km, B) 168km, C) 200km, D) 224km, View Answer, Option B, Solution:, Speed:, 42 : 48, 7:8, Time 8 : 7, ., (+1), 1=30, 8=240minutes = 4hrs, Distance = speed * time, = 42*4, = 168km, 3., Two persons goes from A to B at 12kmph and 8kmph. The faster one reach B first and come, back. He meets slower one at a point R. find the distance between A & R if the distance between A to, B is 20km?, A) 12km, B) 24km, C) 16km, D) 18km, View Answer, Option C, Solution:, it is clear that both person covers double distance ., So 2*20/(12+8) =2hrs, Slower one covers 8*2 = 16km, In that time in which father one covers 12*2 =24km, So 16km is ans, 4., Two trains are running on a parallel track in same direction. Train A comes from behind and, overtake train B in 60seconds. One person in train A observes that he covers train B in 40seconds. If, the speed of trains in the ratio of 3:1, then find the ratio of length of train A & B?, A) 1:3, B) 3:2, C) 2:3, D) 1:2, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , View Answer, Option D, Solution:, In this question speed doesn’t matter because we know …..length = speed*time. Speed remains, same in both cases so it will cancel out., Now length of A+B =60unints, Length of B = 40 units, Length of A = 60-40 =20units, A:B, 20 : 40, 1:2, 5., If a person cover a distance in 5/7th of his normal speed, then he will reach his destination, 20minutes late. Find the usual time taken by him on his normal speed?, A) 100min, B) 50min, C) 140min, D) 70min, View Answer, Option B, Solution:, Shortcut : multiply numerator by time/difference, Difference = 7-5 =2, Time = 20, 5*20/2 = 50min, 6., A man cover a distance in t hrs, if he met with an accident after 20km and he then run at his, 3/5th of his normal speed, so he reach his destination 40minutes late. If he met with an accident at, 30km then he reach only 30min late. Find his original speed?, A) 60kmph, B) 50kmph, C) 40kmph, D) 24kmph, View Answer, Option C, Solution:, After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km., Now speed: after accident, before accident, ., 3, 5, Time, 5, 3, ., (+2), 2=40minutes, 1=20min, (Normal time) 3= 60min, So he covers 40km in 60min with normal speed = 40kmph, 7., A thief steal a car at 1pm and run at a speed of 80kmph. The theft discovered at 2pm and police, run behind him at a speed of 100kmph. Find at what time police will catch the theif?, A) 6pm, B) 7pm, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , C) 8pm, D) 5pm, View Answer, Option A, Solution:, The thief cover 80km in 1hr., Time – 80/(100-80) = 4hrs., So – 2pm+4 = 6pm, 8., A boat travels upstream from Q to P and downstream from P to Q in 3hrs. if the distance, between P to Q is 4km and the speed of the stream is 1kmph, then what is the speed of the boat in still, water?, A) 4.5kmph, B) 5.2kmph, C) 2.5kmph, D) 3kmph, View Answer, Option D, Solution:, Go with options, 4/(3+1) + 4/(3-1) = 3hr, Only option D satisfy, 9., A boat covers 12km upstream and 18km downstream in 3hrs. while it covers 36km up stream, and 24km downstream in 6(1/2) hrs. find velocity of the stream?, A) 1.5kmph, B) 1kmph, C) 2kmph, D) 2.5kmph, View Answer, Option C, Solution:, 12/y + 18/x =3…………..(1), 36/y + 24/x = 13/2……………(2), By solving above equation we will get, X=12kmph, y = 8kmph, Speed of stream = (12-8)/2 = 2kmph, 10., Two person A & B with speed of 30kmph and 40kmph comes towards each other. When they, meet it is find that faster one cover 30km more than slower one, find the distance cover by train?, A) 210km, B) 240km, C) 280km, D) 300km, View Answer, Option A, Solution:, Faster train cover 10km more in every hour. So for 30km the train has to run for 3hrs., , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Distance = (30+40) *3, = 210km, , 1. There are two trains. The speed of trains are x and 2x respectively. Train A started at 8am and train, B started at 9 AM and move towards each other. The distance between them is 600km. they met, each other at 12 Noon. Find the value of x?, A) 120kmph, B) 60kmph, C) 180kmph, D) 90kmph, E) 45kmph, , View Answer, Option B, Solution:, (600 – x)/(x+2x) =3, 10x=600, X=60, 2., A train start from point A and move towards B. it met with an accident after 45km and covered, remaining distance at 2/3rd of its speed and it late by 40 minutes. If the accident happened 15km after, then train would be 30 minutes late. Find the distance?, A) 90, B) 100, C) 105, D) 110, E) 120, , View Answer, Option C, Solution:, It saves 10min in 15 km, So far 40min it cover 15*4 = 60km, So 60 + 45= 105, 3., A man covers a distance in three equal parts. He covers first part at 5kmph, 2nd part at10kmph, and 3rd part at 30kmph. Find his average speed?, A) 10kmph, B) 9kmph, C) 8kmph, D) 15kmph, E) 12kmph, , View Answer, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option A, Solution:, Let X LCM of 5,10,30 =30, Time taken in three parts, 30/5= 6hr(1), 30/10=3hr(2), 30/30= 1hr(3), Average speed = total distance/ total time, = 30+30+30/6+3+1 = 10kmph, 4., There are two trains move towards each other @50kmph and 60kmph respectively. When they, meet it is noted that faster train covers 50km more than the other. Find the total distance travelled by, them?, A) 555km, B) 500km, C) 575km, D) 550km, E) 525km, , View Answer, Option D, Solution:, Faster train cover 10km more in every hour so far 50km it has to run in 5hr., Distance = (50+60) * 5 =550km, 5., Two person A & B walk from P to Q, which are at a distance of 15km at 6kmph and 9kmph, respectively. B reaches Q and returns immediately and meets A at R. find the distance from P to R?, A) 8km, B) 12km, C) 9km, D) 10km, E) 15km, , View Answer, Option B, Solution:, Total distance travelled by both = 30km, Ratio of speed = 2:3, PR = 2/2+3 *30 = 12km, 6., A man walking at a speed of 5kmph reaches his target 5minutes late. If he walks at a speed of, 6kmph, he reaches on time. Find the distance of his target from his house?, A) 2.3km, B) 2.4km, C) 2.5km, D) 2.6km, E) 2.7km, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , View Answer, Option C, Solution:, (5*6/1 )* (5/60) =2.5km, 7., A thief steal a car at 1:30PM and drive at the speed of 80kmph. The theft is discovered at, 2:30pm and police run behind him at the speed of 100kmph. Find at what time thief will be caught?, A) 6:30PM, B) 5:30PM, C) 6PM, D) 7PM, E) 7:30PM, , View Answer, Option A, Solution:, Thief cover distance in 1hr=80km, Time taken by police to caught him = 80/100-80 = 4hrs, 2:30 + 4= 6:30pm, 8., A train after travelling 50km met with an accident and then proceeds at 3/4th of its former, speed and arrived at destination 35min late. Had the accident occurred 24km further, it would have, reached the destination only 15min late. Find the normal speed of the train?, A) 36kmph, B) 40kmph, C) 38kmph, D) 24kmph, E) 12kmph, , View Answer, Option D, Solution:, 20min = 24km, 35min = 42km, Now ratio of speed – normal ……………after accident, 4…………………….3, Ratio of time – 3……………………4, ., (+1) = 35, So 3 = 105 min, 42/105*60 =24kmph, 9., A train passed two persons who are walking in the opposite direction in which the train is, moving at the rate of 6 meter per second (mps) and 10mps in 8 seconds and 6 seconds. Find the length, of train?, A) 96m, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , B) 80m, C) 72m, D) 54m, E) 60m, , View Answer, Option A, Solution:, Let speed of train =X, Length = ( X+6) *8 = ( X+10) *6, 2x = 12, X= 6, Relative speed * time = length, (6+6) *8 = 96m, 10., A train covers a platform in 30 sec and a pole in 10sec. if the length of train is 150m, then find, the length of platform?, A) 400m, B) 450m, C) 500m, D) 300m, E) 550m, , View Answer, Option D, Solution:, Length of train : Length of platform, (x+150)/30 = 150/10, x=300, , 1. Two buses starts from A and B towards each other respectively. They meet at a point X. the speed of, buses are 50km/hr and 60km/hr. when they met they found that faster train covers 40km more than, the slower. Find the distance between A and B., A) 400km, B) 420km, C) 440km, D) 480km, , View Answer, Option C, Solution:, The bus which is faster covers 10km more in an hour. So for 40km it has to take 4hrs., Now the time both the train travelled in 4hrs….., Distance = speed * time, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , (50+60)=110, 110*4= 440, 2., A bus covers a total distance in 12hours. It covers first half at 10km/hr and 2nd half at, 14km/hr. find the distance covered by bus?, A) 140km, B) 120km, C) 160km, D) 145km, , View Answer, Option A, Solution:, This is concept of average speed., So, Distance = average speed * time, = 2*10*14/(10+14) *12 = 140km., , 3., A thief steal a car at 1:30pm and drive at a speed of 60km/hr. Police came to know about theft, at 2:30pm and start chasing him with the speed of 70km/hr. after how much kilometer police will catch, the thief ?, A) 360km, B) 420km, C) 440km, D) 480km, , View Answer, Option B, Solution:, Police came to know about theft after 1hou. So distance between thief and police 60km, now police, start chasing him with a relative speed of 10km/h (70-60), Time taken by police = 60/10 = 6hrs, Distance run by police = 70*6= 420km, 4., A train passes a pole in 30seconds and a platform in 1minute10seconds. If the length of, platform is 160km. then find the length of train ?, A) 100m, B) 80m, C) 160m, D) 120m, , View Answer, Option D, Solution:, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Ratio of length of train : length of platform, 30 : 40, 40=160, 30= 120km, 5., If a bus run without stoppages then the speed of bus is 54km/h and with stoppage the speed, reduces to 36km/hr. find the stoppage time in an hour of bus?, A) 20minutes, B) 15miniutes, C) 10minutes, D) 25minutes, , View Answer, Option A, Solution:, Sol: stoppage time = original speed – stoppage speed *60, Original speed, =(54-36)/54 * 60, = 20 minutes, 6., A person has to reach a place in a certain time and he find that he will be 15minutes late, if he, walks at 4km/h and 10 minutes earlier if he walks at 6km/h. find the distance he has to cover?, A) 3km, B) 4km, C) 5km, D) 6km, , View Answer, Option C, Solution:, s1 * s2/(s2 – s1) * (t1+t2)/60, = 4*6/2 * 25/60, = 5km, 7., A man can reach a certain place in 30hours. If he reduces his speed by 1/15th, he covers 10km, less in that time. Find his speed ?, A) 4km/h, B) 5km/h, C) 6km/h, D) 7km/h, , View Answer, Option B, Solution:, Speed = A : B, ., 15 : 14, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Time = 14 15 (15-1), but we have to keep time same in B also, so distance covered in both cases =, A = 15*14 = 210, B = 14*14 =196, 210-196 =14, 14 =10( 10 km less in question), 210 = 150km, Speed = 150/30 =5km/h, 8., Ravi and Ajay start simultaneously from the same place. A far B 50km apart. Ravi’s speed is, 5km/h less than that of Ajay. Ajay after reaching B, returns and meet Ravi at a place 10km apart from, B. find Ravi’s speed?, A) 10km/h, B) 15km/h, C) 12km/h, D) 20km/h., , View Answer, Option A, Solution:, In the whole journey Ajay covers 20km more than Ravi ., Then time taken by Ajay = 20/5= 4hrs (Because in every hour Ajay covers 5km more than Ravi for, 20 km.), So, Speed of Ajay = 60/4 =15, Ravi’s speed = 15-5= 10km/hr, 9., Walking at 4/5th of his usual speed, a man is 10 minutes late. The usual time taken by him to, cover that distance is ?, A) 36minutes, B) 50minutes, C) 45minutes, D) 40minutes, , View Answer, Option D, Solution:, In this case → numerator * time/(Numerator – denominator), = 4*10/1 = 40minutes, 10., A man cover a certain distance in t hours. If he met with an accident at 50km and he cover, remaining distance at 2/3 of his speed. He covered distance in 30 minutes late. If he met with this, accident at 60km he would late by 24 minutes , then find the distance?, A) 100km, B) 120km, C) 110km, D) 150km, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , View Answer, Option A, Solution:, He saves 6minutes by covering 10km more distance with his normal speed. For 30minutes he cover, 50km and 50km are initial, So distance = 50+50 = 100km., , 1. A man covers a distance in four equal parts. He covers first part with speed of 60 kmph, second part, with 80 kmph and third part and fourth part with 120 kmph and 80 kmph respectively. Find the, average speed of his journey., A) 60 kmph, B) 80 kmph, C) 120 kmph, D) 100 kmph, E) None of these, , View Answer, Option B, Solution:, |—–x——|——-x——–|——-x——-|——-x——-|, 60, 80, 120, 80, Let x= 240 km (LCM of speed), Time= 240/60 +240/80 +240/120 +240/80=4+3+2+3=12 hours, Avd speed=total distance/ total time=240*4/12= 80 kmph, , 2., A thief steals a car at 8 PM and starts driving at a speed of 80 kmph. The theft came into light, at 9 PM and police started to chase him at 9 PM at a speed of 100 kmph. At what time will he be, caught?, A) 2 AM, B) 3 AM, C) 12 PM, D) 1 AM, E) None of these, , View Answer, Option D, Solution:, Thief has moved 80 Km in 1 hour, So distance=80 km, Time= Distance/ relative speed=80/(100-80)= 4 hour, 9 PM+4= 1AM, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , 3., A train starts from P at 8 PM and reaches Q at 11 PM. Another train starts from Q at 6 PM and, reaches P at 11 PM. Find at what time they will meet each other?, A) 9:7.5 PM, B) 8:7.5 PM, C) 10:7.5 PM, D) 9:7.5 PM, E) None of these, , View Answer, Option A, Solution:, Time (A:B)=3:5 => Speed(A:B)=5:3, Let distance=150 km, Speed A= 50 kmph ; Speed B=30 kmph, B starts 6 PM, in 2 hours i.e (till 8 PM when A starts) it will move2*30=60 km, remaining = 150-60=90 km, Time= distance/relative speed=90/80= 1 hour 7 mins 30 sec, hence time=8 PM + 1 hour 7 mins 30 sec= 9:7.5 PM, 4., If a person goes to school fro his home at a speed of 4 kmph, he reaches 10 minute late. If he, goes at a speed of 6 kmph he reaches 10 mins early. Find the distance between school and home, A) 5 km, B) 8 km, C) 6 km, D) 4 km, E) None of these, , View Answer, Option D, Solution:, Direct Formula Distance= [Speed 1*Speed 2/(S1-S2)]* [(Late + Early)//60], =4*6/(6-4)*[(10+10)/60]=4 km, 5., A man takes 7 hours 30 mins in walking to a certain distance and riding back. He would have, gained 3 hours 10 mins by riding both ways. How long he would take to walk both ways?, A) 600 mins, B) 640 mins, C) 680 mins, D) 580 mins, E) None of these, , View Answer, Option B, Solution:, 7 hour 30 mins – 3 hours 10 mins =4 hours 20 mins(When riding both ways), => 2 hour 10 mins riding in one way, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , ride+walk= 7 hour 30 min —(i), ride= 2 hour 10 min –(ii), Diff (i)-(ii)=walk one way=5 hour 20 min, walk 2 way= 10 hour 40 mins=640 mins, , 6., In covering a distance the speed of A and B are in the ratio 4:5. A takes 40 mins more than B to, reach the destination. The time taken by A to reach the destination is?, A) 2(1/3) hours, B) 4(1/3) hours, C) 3(1/3) hours, D) 5(1/3) hours, E) None of these, , View Answer, Option C, Solution:, Speed (A:B)=4:5, Time (A:B)=5:4, Time diff=5-4=1, 1=40 min, 5=200 mins= 3(1/3) hours, 7., Two person cover some distance at a speed of 35 kmph and 40 kmph respectively. Find the, distance if one person takes 15 minute more than the other., A) 60 km, B) 50 km, C) 80 km, D) 70 km, E) None of these, , View Answer, Option D, Solution:, Speed (A:B)=35:40=7:8, Time(A:B)=8:7 ->Diff=1, 1=15, 8=120 min=2 hour, Distance=35*2= 70 km, 8., Two busses start at same time from two stations and move towards each other at the rate of 30, kmph and 35 kmph respectively. When they meet one bus has traveled 60 km more than the other. Find, the distance between the two bus stations., A) 780 km, B) 720 km, C) 680 km, D) 750 km, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , E) None of these, , View Answer, Option A, Solution:, The bus with higher speed moves 35-30=5 km more than the other in 1 hour, means it will move 60 more in 60/5=12 hours, Hence distance=30*12+35*12=780 km, 9., A train crosses a pole in 20 seconds and a platform in 45 seconds. If the length of platform is, 500 meters find the sum of length of train and platform, A) 800 m, B) 900 m, C) 1000 m, D) 950 m, E) None of these, , View Answer, Option B, Solution:, Train : Platform= 20 : 25, 25=500, 20=400, total length=900 m, 10., A train overtakes two persons who are walking in the same direction in which the train is, moving, at the rate of 2 kmph and 4 kmph respectively and passes them completely in 9 seconds and 10, seconds respectively. Find the length of the train., A) 50 m, B) 40 m, C) 60 m, D) 70 m, E) None of these, , View Answer, Option A, Solution:, x/(y-2)*18/5=10 ——(i), x/(y-4)*18/5=9 –(ii), solve and get x=50 m, , The distance between two towns A and B is 545 km. A train starts from town A at 8 A.M. and travels, towards town B at 80 km/hr. Another train starts from town B at 9 : 30 A.M. and travels towards town A, at 90 km/hr. At what time will they meet each other?, A) 11:30 AM, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , B) 12:30 PM, C) 12:00 Noon, D) 1:00 PM, E) 11:00 AM, , View Answer, Option C, Solution:, With 80 km/hr, distance travelled in 1 n half hours (9:30AM – 8AM) is 3/2 * 80 = 120 Km, Now second train also starts, and at this time distance between both trains is (545-120) = 425 km, Relative speed = 80+90 = 170 km/hr (when travelling in opposite direction, add speed), So time when they meet = 425/170 = 2.5 hrs, So after 9:30 AM they meet after 2.5 hrs, so 12 AM,  A bus can travel 560 km in 8 hours. The ratio of speed to train to that of car is 13 : 8. If the speed of bus, is 7/8 of the speed of car, find in how much time train can cover 520 km distance., A) 3 hours, B) 4 hours, C) 6 hours, D) 5 hours, E) 2 hours, , View Answer, Option B, Solution:, Speed of bus = 560/8 = 70 km/hr, So speed of car = 8/7 * 70 = 80 km/hr, So speed of train = 130 km/hr, So time taken by train to cover 520 km = 520/130 = 4 hours,  A person has to travel from point A to point B in car in a scheduled time at uniform speed. Due to some, problem in car engine, the speed of car has to be decreased by 1/5 of the original speed after covering 30, km. With this speed he reaches point B 45 minutes late than the scheduled time. Had the engine be, malfunctioned after 48 km, he would have reached late by only 36 minutes. Find the distance between, points A and B., A) 120 km, B) 80 km, C) 100 km, D) 150 km, E) 70 km, th, , View Answer, Option A, Solution:, Let total distance be d km, speed = u, and time = t hours, So case 1:, 30 km with speed u, (d-30) with speed 1 – 1/5 = 4/5 of u, If he would have travelled (d-30) by speed u, then time = (d-30)/u, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , But now time is = (d-30)/(4u/5) = 5(d-30)/4u, And difference in timings is 45 minutes = 3/4 hour, So 5(d-30)/4u – (d-30)/u = 3/4, Solve (d-30)/u = 3, case 2:, 48 km with speed u, (d-48) with speed 1 – 1/5 = 4/5 of u, If he would have travelled (d-48) by speed u, then time = (d-48)/u, But now time is = (d-48)/(4u/5) = 5(d-48)/4u, And difference in timings is 36 minutes = 3/5 hour, So 5(d-48)/4u – (d-48)/u = 3/5, Solve (d-48)/4u = 3/5, Divide both equations, d = 120 km,  Towns A and B are 225 km apart. Two cars P and Q travel from towards each other from towns A and, B respectively and meet after 3 hours. If the speed of P be 1/2 of its original speed and Q be 2/3 of its, original speed, they would have met after 5 hours. Find the speed of the faster car., A) 50 km/hr, B) 40 km/hr, C) 45 km/hr, D) 30 km/hr, E) 60 km/hr, , View Answer, Option C, Solution:, Let speeds be x km/hr and y km/hr, So 225/(x+y) = 3, And 225/(x/2 + 2y/3) = 5, Solve, x = 30, y = 45,  From point A, Priya and Bhavna start cycling towards point B which is 60 km away from A. The speed, of Priya is 10 km/hr more than the speed of Bhavna. After reaching point B, Priya returns towards point A, and meets Bhavna 12 km away from point B. Find the speed of Bhavna., A) 40 km/hr, B) 15 km/hr, C) 30 km/hr, D) 20 km/hr, E) 45 km/hr, , View Answer, Option D, Solution:, Speed of Bhavna = x km/hr, of priya = (x+10) km/hr, Distance covered by Priya = 60+12 = 72 km, And by Bhavna = 60-12 = 48 km, So, 72/(x+10) = 48/x, Solve, x = 20, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, ,  A train crosses 2 men running in the same direction at speeds 5 km/hr and 8 km/hr in 12 seconds and, 15 seconds respectively. Find the speed of the train., A) 30 km/hr, B) 24 km/hr, C) 25 km/hr, D) 35 km/hr, E) 20 km/hr, , View Answer, Option E, Solution:, Let the speed of the train is s km/hr and its length is a m., So, a/[(s-5)*(5/18)] = 12; [In same direction relative speed is obtained by subtracting. Also changing km/hr to, m/s], Solve 3a = 10s – 50 . . . . . . . . (i), And also, a/[(s-8)*(5/18)] = 15;, 6a = 25s-200 . . . . . . . . . .. . . (ii), Solve (i) and (ii), s = 20 km/hr,  A train which is travelling at 80 km/hr meets another train travelling in same direction and then leaves, it 150 m behind in next 20 seconds. Find the speed of the second train., A) 72 km/hr, B) 53 km/hr, C) 64 km/hr, D) 59 km/hr, E) 65 km/hr, , View Answer, Option B, Solution:, Let speed of the 2nd train is s m/sec., 80 km/hr = (80*5)/18 = 200/9 m/sec., Trains are travelling in same direction. So, (200/9) – s = 150/20, Solve, s = 265/18 m/sec = 265/18 * 18/5 = 53 km/hr,  In a 500 m race C can beat B by 30 m, and in a 400 m race B can beat C by 20 m. Then in 200 m race, A will beat C by how much distance (in m)?, A) 58.2 m, B) 68.4 m, C) 63.5 m, D) 72.8 m, E) 55.2 m, , View Answer, Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart

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Daily Visit: ExamsCart.com, , Free Study Material Join: Telegram.me/ExamsCart, , Option B, Solution:, When A runs 500 m, B runs 470 m, So when A runs 200 m, B runs 470/500 * 200 = 188 m, When B runs 400 m, C runs 280 m, So when B runs 188 m, C runs, 280/400 * 188 = 131.6 m, So A will beat C by (200-131.6) = 68.4 m,  2 towns A and B are 300 km apart. 2 trains start travelling from town A towards town B such that the, second train leaves 8 hours late than the first one. They both arrive at town B simultaneously. If the speed, of the faster train is 10 km/hr more than the speed of the slower train, find the time taken by the slower, train to complete the journey., A) 25 hours, B) 22 hours, C) 14 hours, D) 18 hours, E) Cannot be determined, , View Answer, Option E, Solution:, Let speed of the slower train is x km/hr, then speed of faster is (x+10) kmph., Let faster train takes t hours to cover the distance 300 km, then slower one takes (t+8) hours., Distance is same. So, x/(x+10) = t/(t+8), Solve, 4x = 5t,  A man leaves from point A at 4 AM and reaches point B at 6 AM. Another man leaves from point B at, 5 AM and reaches point A at 8 AM. Find the time when they meet., A) 6:20 AM, B) 6:15 AM, C) 5:45 AM, D) 5:36 AM, E) 5:30 AM, , View Answer, Option D, Solution:, Use formula:, 4 AM + (6-4)*(8-4)/[(6-4)+(8-5)], gives 4 AM + 8/5, 8/5 hours = 1 3/5 hours = 1 3/5*60 = 1 hour 36 minutes, So 4 AM + 1 hour 36 minutes = 5:36 AM, , Please Support Us Like us facebook.com/ExamsCartOfficial& Follow Us On Instagram.com/Exams_Cart