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SOE COMPETITIVE CLASSES, {DUMRAON}, , To remove this notice, visit:, www.foxitsoftware.com/shopping, , Let the least number be x, , In 2nd case, , Now,, , Total number of students who appeared = 4x + 8, , (14-x):(17-x)::(34-x):(42-x), , Total number of students who passed = 3x - 6, , (17-x)×(34-x) = (14-x)(42-x), , Total number of students who failed, , x=2, , = (4x + 8) - (3x - 6) = x + 14, , 2 must be subtracted from each of the number., , Now, we have, 4., , Edited with the trial version of, Foxit Advanced PDF Editor, , (b), , = 1 ⇒ x = 10, , Total number of students is 40., , According to question,, , 3, , x, 1, , =, , 27, , 27×x =, , x=, , 5, , 7., , 7, , (d), According to question, , 9, , 3x  9 12, , 5x  9 23, , 3 9, , 7 5, , ⇒ 69x-207 = 60x-108, , 1, 35, , 9x = 99, x = 11, , 5., , (b), , Second No. is = 5x = 5×11 = 55, , Total students = 720, Ratio of Boys and Girls = 7:5, No. of Boys =, , 7, ×720 = 420, 12, , No. of girls =, , 5, ×720 = 300, 12, , 8., , (d), Suppose the number is ab., We have (10a + b) +, , (10a + b) = 10b + a, , Hence, =, , Now,, According to question, 9., , 420, 1, , 300  x 1, , (a), Given that:, , ⇒ 300+x = 420 ⇒ x = 120 girls., , Number of boys = of 40 = 25, Number of girls = of 40 = 15, , 6., , (c), , Number of boys after 7 boys left = 25-7 =18, , Suppose numbers of students who passed and, , Number of girls after 7 girls joined = 15 +7 =22, , failed are 3x and x respectively., , Required Ratio = 18:22 = 9:11, , Total number of students appearing = (3x + x) =, 4x, 5

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SOE COMPETITIVE CLASSES, {DUMRAON}, 10., , Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping, , The number of white balls ordered = (45, , (b), Maney After deduction = 5783 - (28 + 37 + 18) =, 5700, Now, James Bond Alice, 4, 6, 9, = 19, ↓×300, ↓× 300, 1200, 5700, Share of James = 1200 + 28 = 1228 Rs., , 6) - 45, , = 225., , 15., , (b), B.tech, , :, , MBA, , 4, , :, , 5 → Ratio of students, , 25 : 16 → Ratio of each student fees, 100 : 80, , 11., , (c), , 5 : 4 → Ratio of total Fees, , given, , Fees collected from MBA aspirants, , a c, , b d, , ⇒, , 162000, × 4 = 72000, 9, , from componendo and Dividendo Rule we have,, ab c d, , ab c d, , 12., , 13., , 16., , Let the number to be added to each of the four, numbers be x. By the given condition, we get, , (a), Rabit, , :, , Cut, , 17 × 22, , :, , 17 × 22, , 1, , :, , 1, , (10+ x): (18 +x) : : (22 + x): (38 + x), ⟹ (10+ x)(38 +x) = (18 + x)(22+ x), ⟹ 380 + 48x +, Cancelling, , = 396 + 40x +, , from both sides, we get, , 380 + 48x = 396 + 40x, , (c), Let number are 5x and 8x, , ⟹ 48x -40x = 396 – 380, , 5x  9 8, , 8x  9 11, , ⟹ 8x = 16 ⟹ x =, , 64x + 72 = 55x + 99, 9x = 27, x=3, Lower number = 5x = 5 × 3 = 15, , Therefore, 2 should be added to each of the four, , (c), , (b), Let us represent their shares by the, corresponding letter of their names., , Ratio of white to yellow balls = 6 : 5, , A + B =2C and B + C = 3A, , Difference in number of white and yellow balls, , ⟹ A + 3A -C =2C (since B = 3A – C), , = 6x - 5x = x = 45., , 4A = 3C ⟹ A: C = 3:4, , Therefore, number of white balls now available, = 45, , 2, , given numbers., , 17., 14., , (b), , 6, , 18., 6, , (d)

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SOE COMPETITIVE CLASSES, {DUMRAON}, (Direct Proportion), , (11+x): (15+x) = (17+x): (23+x), , More lines, more cost (Direct Proportion), , 11, , 17, , 15, , 23, , Less words, less cost (Direct Proportion), , 1, , (b), Let r be the 4th proportional., Then, , 20., , To remove this notice, visit:, www.foxitsoftware.com/shopping, , Let x is to be added, , ⟹, , 19., , Edited with the trial version of, Foxit Advanced PDF Editor, , 12 3, , 8a3, , 9a 2, , r, , r, , 23., , Let the prices of two houses A and B be Rs. 4x and, Rs. 5x, respectively for the last year., 4x)and, , 24., , 9, , 50 000, , 21:28, , words, , 11:10, , 10, , 8, , (b), , 3, , 3, , 2, , 2, , ⟹R= Q=(, , Hence, the price of A last year was, , Also,, , 4x = Rs. 3, 60,000, , R, , 2, 3, , 2, R, , 3 ), , 9, , 3, , 3, , 9, , 2, , 2, , 2, , 3, , 2, , ⟹S= R=(, , Thus, P = 2x, Q =3x, R =, , 27, , ), , 4, , and S =, , 27, 4, , Now, P + Q + R + S = 1300, , (b), , ⟹(2, , Let the length and breadth of the rectangular, room be l and b ., l 4, , 4, , 4, , 3, , 3l -4b = 4, , 9, , 27, , 2, , 4, , ⟹ 65x = 5200 ⟹ x =, P’s share = Rs., , ) =1300, , 5200, , 80, , 65, , (2, , 80) =Rs. 160, , ….(1), , Again, we have, ⟹l – 2b = - 4, , 3, , ⟹ (8x+12x+18x+27x) =5200, , 3l + 12 = 4b +16, , 25., , (c), , …(2), Old ratio of student → 2, , Solving (1) and (2), we get l = 12 and b = 8, , 3, +2, , 22., , 10 19, , 3, , Let P = 2x and Q = 3x. Then,, , ⟹x =90,000, , We have,, , 21, , 8, , 28, , (d), , ⟹50x -45x = 450000 ⟹ 5x =4, 50,000, , 21., , 171, , x = 297, , :: 19:x, , From the given options, we just need to look for a, multiple of 7. 2100 is the only option which is a, multiple of 7 and is hence the correct answer., , This year, Ratio of their prices = 9:10, 5, , Lines, , ⟹x=, , (a), , 1.25 4, , 320:297, , 320 21 11, , 6a4, , Then, the prices of A this year = Rs.(1. 25, that of B = Rs. (5x +50,000), , Leaves, , New ratio of student → 4, , (c), , After increase, , Less leaves, less cost, , 2 unit = 20, 7, , +2, 5, , 5, +2, 7

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SOE COMPETITIVE CLASSES, {DUMRAON}, 1 unit = 10, No. of student in starting = 2 + 3 + 5 = 10 unit, 10 unit = 10 × 10 = 100, No. of student in starting = 100, , Alternatively, No. of student is three batch = 2x, 3x, 5x, According to the question, 2x  20 4, , 3x  20 5, , 12x + 80 = 10x + 100, 2x = 20, x = 10, No. of student in three batch = 2x + 3x + 5x = 10x, No. of student in three batch = 10 × 10 = 100, , SOE COMPETITIVE CLASSES, {DUMRAON}, Cont-9931878918, , 8, , Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping