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Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping, , x = 4k, y =9k and z = 36k, , Since, the total amount is not given , we cannot say, , 49k =5390, , anything about A's share, , k =110, The third part = 36 110 = Rs.3960., , 8., , (b), = =, , 4., , (b), Hence, A : B : C = 12 : 4 : 6 = 6 : 2 : 3, , Given that:, , Hence, A + B + C = 11x = 627, , a:b =2:3 and a:d =3:4, , x = 57, , Therefore, a: b: d = 6:9:8, b:d = 9:8 and d:e = 5:4, , So, A = 342 , B = 114, C = 171, , b:d:e = 45:40:32, Therefore, b:e = 45:32, , 9., , (c), A : B : C = 2:3:4, , 5., , (c), , =, , Ratio of white mice to total mice, =, , :, , =1:4, , =, = :1, , =, , Ratio of gray mice to total mice, , =8:9:24, , = :, , Hence required ratio = 8:9:24, , =3:9=1:3= :1, , Ratio of white mice to gray mice = : = 3 : 4, , 6., , 10., , (a), , (b), Ratio of sides =, , 6:4:3, , Largest side = (, , )cm = 48cm, , If = =, Here , p = 4 , q = 15 and r = 29., , 11., , The piece that is cut off should be such that the, fraction of the first to the second alloy in each of, the two new alloys formed should be equal. If you, cut off 4kg, the respective ratios will be: First, alloy: 2kg of first alloy and 4kg of second alloy, Second alloy: 4kg of first alloy and 8 kg of the, second alloy . It can easily be seen that the ratios, are equal to 1:2 in each case., , Hence, answer =, , 7., , (a), , (c), Considering the ratio,, B + C 's share = 20x and A's share = 5x, Hence, the 2nd statement gives no additional, information., , 12., 5, , (c)

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Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping, , Let the initial fraction be, , a, b, , a7 3, , b7 4, , 16., , (a), Let the price of the scooter in the 2 years be 3x, and 7x, respectively., , 4a+28 = 3a+21, 4a – 3b = - 7, , According to the problem,, , Satisfy this condition by options, , 4x = 8000 ⟹ x =2000, , Put value from option (c), , Price of the scooter in the last year = Rs.6000, , 4a – 3b = - 7, , Price of the car last year = Rs.6000 1.25, , 4(2) – 3 (5) = - 7, , = Rs.7500, , 8 – 15 = - 7, Hence the correct answer option (c), , 17., , (c), After two years:, , 13., , (c), , The changed value of the price of the scooter, , Let us first understand the relation between the, points given, , =1.1x, , A, , B, , C, , 60, , 40, , 45, , ↓×2, , ↓×2, , 80, , 90, , The changed value of the price of the bicycle, = 0.8y, Now as per the question,, , C can give 10 points in a 90 points game, , 14., , (a), Let the number of men, women and children be, 3x, 7x and 4x.As the total is 14x, the number of, members in the colony has to be a multiple of 14., , 18., , (b), Let the length of Pencil be ‘x’ cm, , Also, the number has to be greater than 150 and, therefore 154 is the lowest such value possible., , Given that one-eighth part of the pencil is, , Number of children =, , length. 1/2 of this is white which is equal to, , black. Of the remaining is 7/8th of the total, , = 44 children., The total length is, 15., , (c), , (, , As per the problem, we have, , ), , Remaining length of the pencil = (7/16) of x, , a = 3k, b =4k and c = 7k, a +b+ c = 3k + 4k +7k = 14k, 6

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Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping, , and shares of A , B and C in this case was 26 , 39, 19., , (d), , and 52 respectively., , The prices are in the ratio 16:7, and the total value, is Rs.92000., , So it is not A, it is C who gains most., Alternate method:, , The price of the first one is Rs.64000 while the, price of the second one is Rs.28000., , : :, , = 0.5 : ̅̅̅̅̅̅ : 0.25, , The price of the first one decreases by 25%, that, is, Rs.16000, to become equal to Rs.48000., , Thus, C who was getting the least finally got the, , The new ratio is 1:1, and therefore the price of the, second one should increase by Rs.20000 to, become equal to Rs.48000., , This eliminates, , maximum amount., (a) and, , (b), , Thus gain of C = Rs. 117 (, , ), , Percentage change in the price of the second, = Rs. 25, , =, =, 22., , = 71.40%, , (c), As per the problem, after deduction, the remaining, , 20., , amount with A,B and C is in the ratio, , (a), , ,that is,, , 6:4:3, , Let the ratio of boys to girls be x:y.Then, Number of boys who are rank holders = 0.15x, , Now, Rs. 650(750-20-30-50) is to be divided in, the ratio 6:4:3., , Number of girls who are rank holders = 0.7y, , A’s share =, , Rs.300, , C’s share =, , Rs.150, , Number of rank holders = 0.15x +0.7y, Number of students who are not rank holders =, 0.85x + 0.3y, , A’s original share =Rs.300 + Rs.20 =Rs.320, , Now, as per the problem,, , C’s original share = Rs.150+Rs.50 = Rs.200, , (0.15x +0.7y/0.85x +0.3y)=2:7, , Difference in shares = Rs.120, , 1.05x +4.9y = 1.7x +0.6y, 23., , 0.65x = 4.3y, , (b), 0.3x + y = 1.4y, =, , 21., , (c), A ratio of : :, , is equivalent to 6 : 4 : 3, , 24., , (d), The costs are in the ratio 2:3:6 while the, quantities are in the ratio 3:2:1., , So, in this case A, B and C would have got Rs. 54,, 36 and 27 respectively., , The total cost = 6 + 6 +6 = 18, , But actually money was divided in ratio 2 : 3 : 4, 7

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Edited with the trial version of, Foxit Advanced PDF Editor, To remove this notice, visit:, www.foxitsoftware.com/shopping, , Cost of the furniture not accounted for by B, =, , 25., , (c), Let that certain Number is x, Mean proportional between 5 and 22, =, , 22  5  110, , Mean proportional between 45 and x, =, , 45.x, , According to the question,  3 110  45x, Squaring both the sides,, 9 × 110 = 45x,  x = 22, , SOE COMPETITIVE CLASSES, {DUMRAON}, Cont-9931878918, , 8