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then, MAGNET OF MATHEMATICS, (Perfect Institute for Perfect Concept), For: XI & XII (JAC & CBSE Board), By- Roy Sir, (9122575535), 2. Straight line: -, problem on slope : -, J. Slope of the line whase, inclination is 60 with, X-dxis, i's, (a) V3, (b), (d) O, Ans (as, 2., Slope of the line whose, inclination i's, 135 with tve, X-axis is, (a) 1, (b), (C) - 1, (d), Am (C), 3. slope, of, the line which, is equally inclined, With X-axis, (a), (b), (d), Am (C), 4. 94 slope of the line, is, then, inclination With x-axis, (a) 60, (b) 30°, 45, (b), (C), Slope of Line soining points (2,-3), and (-5,1), is, 5., -7, 4, (d) 7, (a), (b), 4, (C), 4, CC), チ, 6. gf line segmont Joining points (2,5) and (X,3) has slope 2, then, x is equal to, (C) 2, (d) - 2, Ans, (b), (b), Ca), 7. gf line jOining points ( 3,y) and (2,7) is parallel to the line, soining through (H,4) and (o,6) then value of y is, CC) 8, Am (a), (b), - 9, (a) 9, 8. 9f line Joining points (-2,6) and (4,8) is Porpendicular to the, line through the points (8,12) and (K, 24) then value of K is, Ans (b), (C) 5, (d) À, (b), 4, a), - 4, Collinear then x is, and (4,5) are, of, points, ((, -1) ,12,1), 9., (d) 1, Anm, (d), (C) 3, (b) 2, 10. The slope of the line which makes an angle of 30' with the positine, antic lockwise, (a), 4, direction of yaris mearured, (b) - V3, Am, (b), (d) -, (C), V3, (a) V3, ib)

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Problem on fquation of straight line:-, Parallel te x-axis or Y-axis:-, 1., Eq: of s line parellel to x-axis, 2 unit below the x-axis ic, and, (a), X = 2, (b) X= - 2, リ= 2, リニ-2, A (d), 2. Eg of St line, 3 unit from it, Parallel, negative side of x-axic, to y-axis and, to wazds, is, (a) X= 3, (b), X= -3, (C), y= - 3, (d) y= 3, An (b), 3 Eq of the line pozpendicular to the, parssing through, X-axis, and, the, point (-1,-1), is, (a), X= -J, (b), (d) y= -1, Ans (a), Slope intercept form:-, The eg of Line, with slupe 3, and y-intscept is -2, is, (a, 3x +y-2 = 0, (b), 3x-y-2 = O, (C) - 3x +y-2 =0, (di none, An (b), 2. The ea, of St line whose intercept on y-axis is 2, and make, an, angle a, with the x-axis such that, Sino = 3, is, (a) 3x -, (b) 3X+ 4 y-2 =0, An (C), 3. The Eg'. of line which, has slope 2, Cut off an intozcept 4, the X-axis, and, on, is, (ai 2x-y -8 = 0, (b) 2x+y-8 = 0, (C) 2x +y +8=0, Ans, (a), Point -slope form:-, S The eg of line, through the point ( 2,-1) and, having slope 2, (C) 2X ty-5=0 (d) none, (a), y = 21+S, (b) y= 20 -S, Au (b), Eq? of the St. line passing thongh Hhe point (2,2) and inclined, 2., to, X-axis at 45°, (a) x-y= o, (b) x+y = 0, () X+ソ-2-0, (dinone, An (a), 3. The ea of Hhe line intersecting x-axis, the left of the origin and, a distanre of 3 uniit to, i's, at, having slope -2, Cb) 2x+y - 6 = 0, (C) 2x+yt6 = 0, (d) none, C), (a) 2x-y-6 =0, 4. The eg? of line inteesoching the y-axis at a distance of 2 unit above, the origin and making an dangle of 30 with the positive direction of x-axis, (C) 13x-y +23 =0 (d) none, (a) x-Vay +213 = 0, The eg. of sd. line which pass through (, 2) and, wth Xー axis, (6) x+V3y+ V3 = 0, Ar (a), are equally inclined, is, (a) メ-y+ =0, (b) X+y- = 0, (C) x +y+3=0, An.

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MAGNET OF MATHEMATICS, (Perfect Institute for Perfect Concept), For: XI & XII (JAC & CBSE Board), By- Roy Sir, (9122575535), 6. The ea! of, St: line passos through ( 3,-2) and, of 60 with the positine direction of x-axis, makes an angle, (a) X-V3y- 3-213=0, (b) X+3y-3-213=0 () V3X-y-3-213=0, Am (a), + The eg of the right bisector of the line segment joining the point, (1,0) and, ( 2,3), (a) X+3y+6=D0, (b) X+3y-6 = 0, (() X-3y+6 = 0, Ans b), The equation of line throrgh the point (o, 2) and, naking, an angle 2%, with, the positive x-axis., (a) 1By +x-2 = 0, (b) V3y-x-2 = 0, -2 = 0, (d) none, Am (C), Two POint form :-, 1. The equation of Straight line passing through the points (-1,1) and (2,-4) is, (a) 5x + 3y +2 =0, Ar (a), (b) 5x-3y+2=0, 2. The equation of line passen thruugh the points (0,1) and mid- point of, (C) 3X +Sy +2 =0 (d) none, Line, Joining segmant pointo (!,2) and ( 3, 6) is, (a) 3x-2y+2 =, (b), () 3X+2y +2 =0 (d) none, Am (a), 2X -, x-3y+2=D0, Intercept form:-, 1. The equation of the line whose intercepts on x-axis and Y-axis are 2 and, - 3 respectively is, (O 2X-3y=, (d) none, An (a), (a) 2x+3y = 6, (b) 3x-2y = 6, 2. The equation of the line which passes through the point ( 3,3) and, (d) none, Cut off, equal Inter(epts on the ax-es., (b) X+y = 6, An (b), (C) X+y= 3, 131, (a) x+y = !, 3, The equation of the line which paassen through (1,2) and whose intercept, on X-axis is double Hhat on the y-axis., (C) X+2y =5, (d) none, As (), (b) 2X-4=5, (a) X- 24=5, 4. The equetiòn of the linı which passo thruugh (ol,-1) and, (d) (+y=1, whose inteeept, axes are equal but Opposite jn Sign is, (C) X+y= 2, Ans (b), on, (b) X-y= 2, (a) x-y=1, Near Jhinjhariya Pool, St. Columba's College Road, Hazaribag- 825301

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MAGNET OF MATHEMATICS, (Perfect Institute for Perfect Concept), For: XI & XII (JAC & CBSE Board), 3., By- Roy Sir, (9122575535), on para metric form:-, J. The Co-ovrdinae of points on line 3X-4y-1 =o that are, away from the point (3,2). ane, (9) o (0) 4409 (), 2. The distance of the point ( 2,5) from the line, (g't) o), ()-'1-) 19), mesured parailel to a line hauing slope 3, (a) 4, 5!, (), 3. The distance of the point (3,5) from the line 2x434 + 14 meastred, S 19), t (p), parallel to the line x-2y- 1, (9) E, Am (C), 우 (a), (P), Reduction of general equation in differont forms:-, di slope intence pt form of ea", 3x+ 3y=, i!, (い), 5., (b) y = 3x-5, %3D, cl) none, Intercept form of ea! 3n 4 2y, S+ x - =h ), 2., つ)形, 9 =, (() (d) none, t., +文 (9), て, 3. Normal form of the St line V3 x +4 -8 = 0, 19), () x Cos 30 + y sin36 = 4, %3D, 4. Normal form of the ea, (৮) ৮, 0ここ-R+x, 5. Normal form of Bx+y + 2 = 0 is, (9) x Cos 120 + y Sin120 = 1, 1ニ, -, (2) at 1=, 6. Normal form of S4. line, X- 4 = 0 1's, %3D, (9), --T:----I r